Circuit Diagram Of Potentiometer To Compare Emf Of Two Cells

Write the working formula derivation not required.

Circuit diagram of potentiometer to compare emf of two cells. Connect the positive poles of the cells to the terminal and the negative poles to the terminal a and b of the two way key. Suppose aj 1 l 1 is the balancing length for cell e 1. We will study here about comparison of emf of two cells using potentiometer.

Insert the plug in the key k and also in between the terminals a and c of the two way key. Remove the insulation from the ends of the connecting copper wires with a sand paper. D is connected directly to a and f is connected to a sliding contact on the potentiometer wire via a sensitive centre zero galvanometer.

By closing key k 1 the cell e 1 is included in the circuit. Arrange the apparatus as shown in circuit diagram figure. When 1 and 3 are connected e 1 is connected to the galvanometer g.

Potentiometer a leclanche cell a daniel cell an ammeter a voltmeter a galvanometer a battery battery eleminator a rheostat of low resistance a resistance box a one way key a two way key a jockey a set square connecting wire a piece of sand paper. Of two given cells and l 1 and l 2 are the corresponding balancing lengths on potentiometer wire. Comparison of emf of two cells.

Comparison of emfs of two primary cells. See that e e 1 and also e e 2. The following figure shows an application of the potentiometer to compare the emf of two cells of emf e 1 and e 2.

Arrange the apparatus as shown in the circuit diagram. Applications of potentiometer for comparing emf of two cells. To compare the e m f s of two cells by using a potentiometer in the circuit diagram of fig.